function sameElementsNaive(a, b) {
var count =0;
for(i=0;i<a.length;i++){
for(j=0;j<b.length;j++){
if(a[i]==b[j]){
count++;
break;
}
}
}
return count;
}
Here Two inputs to the function are integer arrays (can be change to other data types as well).
Ex:
sameElementsNaive([1,2,3], [3,4,5]);
this function call should return 1 because only 3 is duplicated in the second array.
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